Farmers’ Market, Chickens, Geese

At the Farmer’s Meat Market, Theo will sell you a certain number of geese for $27. Four more chickens than that cost $42. Six chickens and two geese will cost you $45. How much would you have to pay for one chicken? How much for one goose?


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Let n be the “certain number” of geese that cost $27, g be the price of a goose, and c be the price of a chicken. (We quail at the large number of variables, but there are no quails in this problem, so we proceed bravely.)

  1. ng = $27, or g =
  2. (n + 4)c = $42, or c =
  3. 2g + 6c = $45.

We get everything in terms of n by substituting for g and c in (3), using (1) and (2):

Clearing of fractions, we get:

6(n + 4) + 28n = 5n(n + 4) → 6n + 24 + 28n = 5n2 + 20n.

Putting in standard quadratic form, we have:

5n2 – 14n – 24 = 0 → (5n + 6)(n – 4) = 0 → n = or n = 4.

In this context, n = 4, so g = 27/4 = 6.75. Substituting the value of g into (3), we find c = 5.25.

Thus a goose costs $6.75 and a chicken costs $5.25.

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