If a v b means ab + 1 and a @ b means a + b, then evaluate
4 v ((6 @ 8) @ (3 v 5))
4 v ((6 @ 8) @ (3 v 5))
= 4 v ((6 + 8) @ (3
5 + 1))
= 4 v (14 @ 16)
= 4 v (14 + 16)
= 4 v 30
= 4 30 + 1
= 121
= 4 v ((6 + 8) @ (3
5 + 1))= 4 v (14 @ 16)
= 4 v (14 + 16)
= 4 v 30
= 4
30 + 1= 121