If a v b means ab + 1 and a @ b means a + b, then evaluate

4 v ((6 @ 8) @ (3 v 5))

4 v ((6 @ 8) @ (3 v 5))

= 4 v ((6 + 8) @ (3 5 + 1))

= 4 v (14 @ 16)

= 4 v (14 + 16)

= 4 v 30

= 4 30 + 1

= 121

= 4 v ((6 + 8) @ (3 5 + 1))

= 4 v (14 @ 16)

= 4 v (14 + 16)

= 4 v 30

= 4 30 + 1

= 121