Dino, Kyle, and Nina race the 100 meters from school to the bus each day. They have found that Dino and Kyle will reach the bus together if Dino is given a head start of 20 meters. Kyle and Nina will arrive together if Kyle is given a head start of 25 meters. If Dino and Nina want to arrive at the bus at the same time, who should start where?
Nina runs 100 m when Kyle runs 75 m = 0.75(100) m.
Kyle runs 100 when Dino runs 80 = 0.8(100) m.
Kyle runs 75 m when Dino runs 0.8(75) = 60 m.
So when Nina runs 100 m, Kyle runs 75 m, and Dino runs 60.
So if Nina and Dino are to arrive at the bus simultaneously, Dino needs a head start of 40 m.