| nx | + | y | = | 1 | ||
| ny | + | z | = | 1 | ||
| x | + | nz | = | 1 |
If n is a real number, then the simultaneous system to the right has no solution if and only if n is equal to:
- -1
- 0
- 1
- 0 or 1
- ½
| nx | + | y | = | 1 | ||
| ny | + | z | = | 1 | ||
| x | + | nz | = | 1 | ||
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|
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| nx + y + ny + z + x + nz | = | 3 | ||||
(n + 1)(x + y + z) = 3
This can be true unless n = -1.
The answer is (a).