If *a* = log_{8}225 and *b* = log_{2}15, then what’s *a* in terms of *b*?

*a*=*b*/2*a*= 2*b*/3*a*=*b**b*=*a*/2*a*= 3*b*/2

*a*= log

_{8}225

8

^{a}= 225 = 15

^{2}

(2

^{3})

^{a}= 15

^{2}

2

^{3a}= 15

^{2}

2

^{3a/2}= 15

*b*= log

_{2}15

2

^{b}= 15

2

3

^{3a/2}= 2^{b}3

*a*/2 =*b**a*= 2*b*/3.The answer is (b).