If r > 0, then for all p and q such that pq does not equal 0 and such that pr > qr, we have:
- –p > –q
- –p > q
- 1 > q/p
- 1 < q/p
- none of these
Since r is not equal to 0, we can divide by r, and since r > 0 we know pr > qr implies p > q. We have three possibilities to consider, so let’s try specific values.
Note: p < 0 and q > 0 is impossible since p > q.
|–p > –q||–p > q||1 > q/p||1 < q/p|
Since none of the conditions (a), (b), (c), or (d) holds for every possibility of p and q, we conclude that (e) is the correct response.