Consecutive Integers, Sum of 17802

Find four consecutive integers whose sum is 17802.


Show/Hide Solution

The four numbers will each be about ΒΌ of 17802, which is 4450.5. Take two numbers on each side of 4450.5 and we have 4449, 4450, 4451, and 4452, which sum to 17802.

Or write an equation: x + (x + 1) + (x + 2) + (x + 3) = 17802.

Leave a Reply

Your email address will not be published. Required fields are marked *