Find four consecutive integers whose sum is 17802.

The four numbers will each be about ¼ of 17802, which is 4450.5. Take two numbers on each side of 4450.5 and we have 4449, 4450, 4451, and 4452, which sum to 17802.

Or write an equation: *x* + (*x* + 1) + (*x* + 2) + (*x* + 3) = 17802.