Consecutive Integers, Sum of 17798

Find 4 consecutive integers whose sum is 17798.


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The four numbers will each be about 1/4 of 17798, which is 4449.5. Take two numbers on each side of 4449.5 and we have 4448, 4449, 4450, and 4451.

Algebraically, let the numbers be x, x + 1, x + 2, and x + 3. Then we can write the equation x + (x + 1) + (x + 2) + (x + 3) = 4x + 6 = 17798, and go from there.

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