The screencast was about solving MT2 problems, no new material was covered. It will be uploaded as soon as the technical issues have been resolved.
Note that E is connected to the 0 marking on the decoder and F to 1. This means that if we look at the truth table to determine the min-terms, E will be in the lowest significant column and F in the higher, i.e., the pair should be read as FE and not EF. Therefore E=0 and F=1 should be read as 10 and not 01 and will correspond to min-term m2. This is why register C gets connected to the bus for E=0 and F=1.
Problem 2 statement in the last version (MT2_sample_sol.pdf) was a bit confusing; it has been rewritten to be more clear in the new version (MT2_sample2_sol.pdf). I have now removed the statement “Ignore Problem 2” from our web site.
Lessons 14, 15, 18, 19, 20, 21 (excluding design), 23
Screencasts: 14, 15, 16, 17, 18, 19, 20, 21, 22, 23 (excluding design), 25